log (5x-4)-log(x+1)=log4
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Answered by
18
log(5x-4)-log(x+1) = log4
log[(5x-4)/(x+1) ] =log4
= (5x-4)/(x+1) =4
5x-4 =4x+4
x = 4+4 =8 ans
log[(5x-4)/(x+1) ] =log4
= (5x-4)/(x+1) =4
5x-4 =4x+4
x = 4+4 =8 ans
Answered by
47
HELLO DEAR,
log(5x - 4) - log(x + 1) = log4
log [ (5x - 4)/(x + 1) ] = log4
[ log(a / b) = loga - logb ]
(5x - 4)/(x + 1) = 4
(5x - 4) = 4x + 4
5x - 4x = 4 + 4
X = 8
I HOPE ITS HELP YOU DEAR,
THANKS
log(5x - 4) - log(x + 1) = log4
log [ (5x - 4)/(x + 1) ] = log4
[ log(a / b) = loga - logb ]
(5x - 4)/(x + 1) = 4
(5x - 4) = 4x + 4
5x - 4x = 4 + 4
X = 8
I HOPE ITS HELP YOU DEAR,
THANKS
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