log 5x minus 1 to the base 1 by 3 is greater than zero
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HELLO THANK YOU FOR SUCH TYPES OF QUESTIONS : - )
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OUR QUESTION IS
log ( 5x - 1 ) base 1/3 > 0
now we will anti log it but one thing i want to tell you if base lies from (0,1) ≠1
while taking antilog inequality of sine will reverse
5x - 1 < 1
x < 2/5 now which means x > 0 but < 2/5 so x lies from ( 0 , 2 /5 )
=========================================================
=========================================================
OUR QUESTION IS
log ( 5x - 1 ) base 1/3 > 0
now we will anti log it but one thing i want to tell you if base lies from (0,1) ≠1
while taking antilog inequality of sine will reverse
5x - 1 < 1
x < 2/5 now which means x > 0 but < 2/5 so x lies from ( 0 , 2 /5 )
=========================================================
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