Question

log 64 / log 8 =log x .....solve for x

Answer 1

 $\frac{log64}{log8}$  = log x 

$log [64-8] = logx$

56 = x 



i hope this will help you


-by ABHAY

Answer 2

Given,

$\frac{log 64}{log 8} = log x$

To Find,

Value of x

Solution,

Since $log$$x^{2} = 2 log x$

Thus $log 64 = log 8^{2} = 2 log 8$

Thus $\frac{log 64}{log 8} = \frac{2 log 8}{log 8}$$= 2$

Since it is stated that $\frac{log 64}{log 8} = log x$

⇒ $log x = 2$

Since in any logarithm if the base is not stated, it is implied that the base is 10, thus $log 100 = log 10^{2} = 2 log 10$ and the value of $log 10 = 1$

Thus value of $x = 100$

Henceforth the value of x = 100.