Math, asked by ranamadhav06, 2 months ago

log 64/ log x=log 256/log1024​

Answers

Answered by akhilmukkara
0

Answer:

Step-by-step explanation:

Now,

Given logarithmic expression

log x / log 4 = log 64 / log 256

log x / log 4 = log 4³ / log 16²

log x / log 4 = 3 log 4 / 2 log 16

(Using the property of logarithms)

[log mⁿ = n log m]

log x = (3/2) [(log 4)² / log 16]

log x = (3/2) [(log 4)² / log 4²]

log x = (3/2) [(log 4)² / 2 log 4]

log x = (3/2) [(log 4) / 2]

log x = (3/4) [(log 4)]

[log 4 = 0.6020, Rounding off the value to 0.6 (From Log Table)]

[For Calculations I used rounding off, if you want exact answer you can do without rounding off and calculate the Antilog after Multiplication and Division]

we get,

log x = (3/4 * 0.6)

log x = (3/4 * 6/10)

log x = (9/20)

log x = 0.45

x = Antilog (0.45)

x = AL (0.45)

[Al (0.45) = 2.818 (From Antilog Table)]

x = 2.818  (ANSWER)//

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