log 64 to the base 2 under root 2 answer this question ❓ it's urgent
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Answered by
0
Answer: 12
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Answered by
1
Answer:
log 64 to the base sqrt(2)
=log 64/log√2
=log 2^6 / log 2^(1/2)
=6 * log 2 / (1/2)* log 2
=6 / (1/2)
=6*2
=12
Step-by-step explanation:
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