Question

Log(6x+4)-log(2x-1)=log 2

Answer 1

Answer:

x = -3

Step-by-step explanation:

$log(6x+4) - log(2x-1) = log(2)\\\\log(\frac{6x+4}{2x-1})= log(2)\\\\\frac{6x+4}{2x-1} = 2\\\\6x+4 = 4x-2\\\\2x = -6\\\\x = -3$

Answer 2

Answer:

$log(6x + 4) - log(2x - 1) = log2 \\ log{(6x + 4) \div (2x - 1)} = log2 \\(6x + 4) \div (2x - 1) = 2 \\ 2(3x + 2) \div (2x - 1) = 2 \\ (3x + 2) \div (2x - 1) = 1 \\ 3x + 2 = 2x - 1 \\ 3x - 2x = - 1 - 2 \\ x = - 3$