Question

log 7*log 5 underroot x square +5+x =0​

Answer 1

Answer:

Consider the given equation.

log

7

log

5

(

x+5

+

x

)=0

log

5

(

x+5

+

x

)=7

0

=1

x+5

+

x

=5

1

=5

x+5

=5−

x

On squaring both sides, we get

x+5=25+x−10

x

x

=2

x=4

hence it is proved