log 7*log 5 underroot x square +5+x =0
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Answer:
Consider the given equation.
log
7
log
5
(
x+5
+
x
)=0
log
5
(
x+5
+
x
)=7
0
=1
x+5
+
x
=5
1
=5
x+5
=5−
x
On squaring both sides, we get
x+5=25+x−10
x
x
=2
x=4
hence it is proved
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