Question

log(8)^(1)/32=x. Find the value of x

Answer 1

$log_{8}( \frac{1}{32} ) = x \\ = - log_{8}(32) \\ = - \frac{ {log \: 2 {}^{5} }}{log {2}^{3} } \\ = \frac{ - 5}{3} \\ \\ mark \: it \: brainliest$