Question

Log 8 is K, log 6 is I then log 4.8 to the base 10 is what

Answer 1

Answer:

log 4.8 = K + I - 1

Step-by-step explanation:

$heya! \\\\ log8=K \\ log 6 = I \\ log 4.8 = ?\\\\=>log \ 4.8 =log \frac{ (8)(6)}{10} \\ \\ log (mn) = log \ m + log \ n\\log\frac{a}{b} =log \ a - log \ b \\\\=>log4.8=[log \ 8 + log \ 6 ]-log \ 10 \\\\=> log 4.8 = [K+I] - log 10\\\\ \ [log 10 = 1]\\\\=> log 4.8 = [K+I]-1\\\\=>log 4.8 = K+I-1 \\\\hope \ it \ helped ...!$