Question

log (81/16)-log (8/9)+log (128/243)

Answer 1

log(81/16) - log(8/9) + log (128/243)

= log[ (81/16)/(8/9)] + log (128/243)         [ Since loga-logb = log(a/b) ]

= log[81×9/ 16×8] +log (128/243)

= log(729/128) + log (128/243)

= log [(729/128)×(128/243)]            [ since loga+logb = log(ab) ]

= log(729/243)

= log3