Question

log(81/48) +log(24/27) +log(5/16)=log 5-log 3-5log 2
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Answer 1

Answer:

please check the question

Step-by-step explanation:

$log( \frac{81}{48} ) + log( \frac{24}{27} ) + log( \frac{5}{16} )$

$= log( \frac{27}{16} ) + log( \frac{8}{9} ) + log( \frac{5}{16} )$

$log( \frac{ {3}^{3} }{ {2}^{4} } ) + log( \frac{ {2}^{3} }{ {3}^{2} } ) + log( \frac{5}{ {2}^{4} } )$

$= log( {3}^{3} ) - log( {2}^{4} ) + log( {2}^{3} ) - log( {3}^{2} ) + log(5) - log( {2}^{4} )$

$= 3 log(3) - 4 log(2) + 3 log(2) - 2 log(3) + log(5) - 4 log(2)$

$= log(5) + log(3) - 5 log(2)$