Question

log 81 to base 2 ÷ log 9 with base 2

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Answer 1

Answer:

2

Step-by-step explanation:

$= log_{2}81 \div log_{2}9 \\ = log_{2}( {9}^{2} ) \div log_{2}(9) \\ = 2log_{2}(9) \div log_{2}(9) \\ = 2$