Question

log 84 base 3 - log 28 base 3 - 3^log 1 base 3​

Answer 1

Answer:

0

Step-by-step explanation:

$log_{3}(28) - log_{3}(28) - {3}^{ log_{3}(1) }$

$= log_{3}(84 \div 24) - {3}^{0}$

$1 - 1 = 0$