Question

log 84 base to 3 - log 28 base to 3 - 3 log 1 base to 3​

Answer 1

Answer:

1.893

Step-by-step explanation:

y = log3 84

= log(3 x 2 x 2 x 7)

= log3(3) + log3(2) + log3(2) + log3(7)

= 1 + 0.6309 + 0.6309 + 1.7712

= 4.033

log3(84) = 4.033

Log(28)to base(3)= (log28)/{log(3)}

log(28) = log7 + log4

Log4=2{log(2)}

so log28= log7 + 2log2

Log28=0.845+2(0.301)=1.449

Log28 base(3) = 1.449/0.477=3.14…

log3(1/3)

=log3^-1 to base 3

= -1*log3 to base 3=-1

4.033 - 3.14 - (-1)

4.033 - 3.14 + 1

1.893

hope it helps u

Answer 2

Answer:

1

Step-by-step explanation:

$log_{3} 84 - log_{3} 28 - 3log_{3} 1$,

$log_{3} 84 - log_{3} 28 - 3(0)$, [ because log 1 to the base of anything is 0]

$log_{3} 84 - log_{3} 28 - 0$,

$log_{3} (\frac{84}{28}) - 0$, [ because $log_{x}m - log_{x}n = log_{x}(\frac{m}{n} )$]

$log_{3} (3) - 0$

$1 - 0$ [ because $log_{m} m = 1$]

= 1