Question

Log 9=a eprees log300 and log √ 0.009 in terms of a

Answer 1

$log(3) = \frac{a}{2}$
$log(300) = log(3) + log(100) = \frac{a}{2} + 2$
$log( \sqrt{0.009} ) = \frac{a}{2} - \frac{3}{2}$