Question

log 97-56root3/log root (7+4root3) equals to?​

Answer 1

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97 - 56√3

= ( 7 - 4√3 )²

49 + 48

-2×7×4√3

97-56√3

2×log(7-4√3)/½×log(7+4√3)

7-4√3 = 1/7+4√3

7²-(4√3)² = 1

x²-y² = (x-y)(x+y)

1 = (7-4√3)(7+4√3)

log(7-4√3) = -log(7+4√3)

4x - 12

= -4

• I Hope it's Helpful •