Question

log, a = 3, log3b = 2, log4 c = 1
Find the value of 3a + 2b - 10c​

Answer 1

Answer:

Log2à=3

a=2^3

Log3b=2

b=3^2

Log4c=1

C=4^1

3a+2b-10c

=3×8+2×9-4×10

=42-40

=2

Answer 2

The value is $3a + 2b - 10c=2$.

Step-by-step explanation:

Given : $\log_2a=3,\ \log_3 b=2,\ \log_4 c=1$

To find : The value of 3a + 2b - 10c​ ?

Solution :

Using logarithmic property, $\log_a b=c\Rightarrow a^c=b$

$\log_2a=3\Rightarrow a=2^3$

$\log_3b=2\Rightarrow b=3^2$

$\log_4c=1\Rightarrow c=4^1$

Substitute the value of a,b and c,

$3a + 2b - 10c=3(2^3)+2(3^2)-10(4^1)$

$3a + 2b - 10c=3(8)+2(9)-10(4)$

$3a + 2b - 10c=24+18-40$

$3a + 2b - 10c=2$

Therefore, the value is $3a + 2b - 10c=2$.

#Learn more

Topic: Logarithms  1. Convert the following into  exponential form. log3b = 10​

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