log(a-b)/2= 1/2(log a+log b)
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THIS SHOULD BE YOUR QUESTION
If log {a+b} /2 = 1/2 (log a+ log b) , prove that a = b?
Step-by-step explanation:
log (a + b)/2 = 1/2 (log a + log b)
=> log (a + b)/2 = 1/2 log ab
=> log (a + b)/2 = log ab^(1/2)
=> (a + b)/2 = ab^(1/2)
=> (a^2 + b^2 + 2ab)/4 = ab
=> a^2 + b^2 + 2ab = 4ab
=> a^2 + b^2 - 2ab = 0
=> (a - b)^2 = 0
=> a - b = 0
=> a = b
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