Question

log(a+b/2)=1/2(log a + log b)

Answer 1

Step-by-step explanation:

LHS = RHS

log (a+b/2) = 1/2(log a + log b)

we use the property (log m + log n) = log (ab)for RHS

LHS = RHS

log (a+b/2) = 1/2 log (ab)

log (a+b/2) = log (ab) to the power 1/2

a+b/2 = (ab )*1/2

a+ b =

$2 \sqrt{ab}$