Question

log a+b ÷3= 1÷2 log ab​

Answer 1

Answer:

true please mark me as a brainiest

Answer 2

Answer: Please write the problem less ambiguously: If

Please write the problem less ambiguously: If a2 + b2 = 7ab

Please write the problem less ambiguously: If a2 + b2 = 7abProve

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules log xy = log x + log y

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules log xy = log x + log y n log x = log xn

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules log xy = log x + log y n log x = log xnNotice that the given includes a2 + b2, as well as terms with ab, so it is also worth remembering that

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules log xy = log x + log y n log x = log xnNotice that the given includes a2 + b2, as well as terms with ab, so it is also worth remembering that a2 + 2ab + b2 = (a + b)2

Please write the problem less ambiguously: If a2 + b2 = 7abProve log( (a+b)/3 ) = (1/2) (log a + log b)The a+b/3 threw me off for a bit, so I almost didn't respond.The first two things to consider is simplifying (log a + log b) and taking care of the (1/2) by multiplying both sides by 2.Remember two important log rules log xy = log x + log y n log x = log xnNotice that the given includes a2 + b2, as well as terms with ab, so it is also worth remembering that a2 + 2ab + b2 = (a + b)2The "creative problem solving" part is to add 2ab to both sides, then things should fall in to place.

Step-by-step explanation:

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