Question

log (a+b+c)=loga+log b+log c

Answer 1

log( a + b + c ) = loga + logb + loga
log( a + b + c ) = log( a× b × c )
a + b + c = abc
a + b + c -abc =0

Answer 2

we know that,
log(a*b*c)= loga + logb +logc
therefore, the given eqn -
log(a+b+c)=log(abc)
log(a+b+c)  -  log(abc) = 0
log{(a+b+c)/(abc)}  =  0
(a+b+c)/(abc)  = 1
a+b+c = abc