Question

log(a+b) +log(a-b)–log(a²-b²)=?
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Answer 1

Step-by-step explanation:

Given :-

log(a+b) +log(a-b)–log(a²-b²)

To find :-

Find the value of the given expression ?

Solution :-

Given expression is log(a+b) +log(a-b)–log(a²-b²)

We know that

log xy = log x + log y

=> log [(a+b)(a-b)] - log (a²-b²)

=> log (a²-b²) - log (a²-b²)

We know that

log x/y = log x -log y

=> log (a²-b²)/(a²-b²)

=> log 1

=> 0

The value is 0

Answer:-

The value of the given expression is 0

Used formulae:-

→ log xy = log x + log y

→ log x/y = log x -log y

→ log 1 = 0