log a B log b C =?
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Hey Buddy
Here's The Answer
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Here we'll be using the below logarithm property.
=> logₓ ( y ) = log y / log x
Now,
==> logₐ v × logᵥ c
=> log v/log a × log c/log v
cancelling log v
=> log c / log a
=> logₐ c
Hope It Helps.
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