Question

log a log b
b-CC-a
logc
a-b
then prove that a b c = 1.​

Answer 1

Answer:

What is meant by b - CC - a

Step-by-step explanation:

FOLLOW ME

Answer 2

Answer:1

Step-by-step explanation:

Let : ( log a ) / ( b-c ) = ( log b ) / ( c-a ) = ( log c ) / ( a-b ) = k.

∴ ( a. log a ) / a(b-c) = ( b. log b ) / b(c-a) = ( c. log c ) / c(a-b) = k

∴ log (a^a) = k.a(b-c), log (b^b) = k.b(c-a), log (c^c) = k.c(a-b)

∴ [ log (a^a) ] + [ log (b^b) ] + [ log (c^c) ]

. . . . . . . . . = k [ ( ab - ca ) + ( bc - ab ) + ( ca - ab ) ]

∴ log [ (a^a)(b^b)(c^c) ] = 0 = log [ 1 ]

∴ (a^a)(b^b)(c^c) = 1