Question

log a+log b=log(a+b) then a=​

Answer 1

log ab = log(a+b)

ab = a+b

a = (a+b)/b

Answer 2

Answer:

$\large\boxed{b=\frac{a}{10^a-1} }$

Step-by-step explanation:

To solve this problem, only had to do is use log formula.

Given:

log a+ log b=log (a+b)

Solutions:

First, you have to use log rule.

$\large\boxed{\textnormal{Log Rule}}$

$\displaystyle a=\log _b(b^a)$

$\displaystyle a=\log _{10}(10^a)$

$\displaystyle \log _{10}(10^a)+\log _{10}(b)=\log _{10}(a+b)$

$\large\boxed{\textnormal{Log Rule}}$

$\displaystyle \log _c(a)+\log _c(b)=\log _c(ab)$

Solve.

$log_1_0(10^ab)=log_1_0(a+b)$

$\displaystyle 10^ab=a+b$

$\displaystyle 10a^b=a+b=b=\frac{a}{10^a-1}$

$\large\boxed{b=\frac{a}{10^a-1}{=a<0, a>0} }$

The correct answer is b=a/10ᵃ-1{A<0 and A>0}.