Question

log a M + log a N = ?​

Answer 1

Step-by-step explanation:

i think log man ,log a mn is this right

Answer 2

logₐM + logₐN = logₐMN

Given :  logₐM + logₐN

To Find : Simplify

Solution:

Using property :  logₐb +   logₐc  = logₐ(b × c)

logₐM + logₐN

=   logₐ(M×N)

= logₐMN

logₐM + logₐN = logₐMN

Here is proof of property  logₐb +   logₐc  = logₐ(b × c)

=> p + q =  logₐ(b × c)

logₐb = p   => b =  $a^p$

logₐc = q  =>  c=   $a^q$

b x c  = $a^p$ x $a^q$

Using law of exponent  xᵃ * xᵇ = xᵃ⁺ᵇ

b x c  = $a^{p+q}$

=> log ₐ (b x c) = p + q

=>  log ₐ (b x c) =   logₐb  +  logₐc

Learn More:

Without using log table, prove the following: i) [tex]rac{3}{10 ...

brainly.in/question/7853475

LIKE THIS :-making use the cube root table find the cube roots of the ...

brainly.in/question/20452788