Math, asked by nk103879, 5 months ago

log(a2/bc)+log(b2/ac)+log(c2/ab)=

Answers

Answered by anuradhasri020785

0

Answer:

logX + logY = log (XY)

= log (a2/bc) + log (b2/ac) + log (c2/ab)

= log (a2 b2 c2 / bcacab)

= log (a2 b2c2 / a2b2c2)

= log 1

= 0

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