log a2base =3,log b2base 3=2,log cto base 4=1 find the valve of 3a + 2b- 10c
Answers
Answered by
0
QUESTION
i think the question says
log(base 2) a =3
log(base 3) b =2
log(base 4) c =1
ANSWER: the value of 3a +2b -10c = 2
-The calculation involves change of base rule
-Consider the first equation,
log(base 2) a =3
=> log(base e) a / log(base e) 2 =3
or we can write, (ln a)/(ln 2) = 3
from here we can find a by simple manipulation, a = 2^3 = 8
-Similarly we can find the values of b and c to be
b = 3^2 = 9
c = 4^1 = 4
-Use these a,b,c in the equation to find the value of the expression
Answered by
0
3a + 2b- 10c = -19
Step-by-step explanation:
Given:
Log a (base1) = 3 implies a = 1^3, so a = 1
Log b (base3) = 2 implies b = 3^2, so b = 9
Log c (base4) = 1 implies c = 4^1, so c = 4
3a + 2b- 10c = 3 (1) + 2 (9) - 10 (4)
= 3 + 18 - 40
= -19
So 3a + 2b- 10c = -19
Similar questions