log (ax+b ) derivative with proper explanation
Answers
Answered by
1
let y= log(ax+b)
dy/dx = d(log(ax+b))/dx
dy/dx = 1/(ax+b) *d(ax+b)/dx
dy/dx = 1/(ax+b)*a
dy/dx = a/(ax+b)
HOPE...!!!IT HELPSSS!!!
Similar questions