log( b)√8= 16÷3 then b=
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Answer:
This question can be solved by 3 basic logarithmic rules.
1.logb(m^n) = n · logb(m)
2. logb^n(m) = 1/n.logb(m)
3 . logb(x) = c, then x = b^c
sqrt(8) can be written as 2^3/2.
Now plugging it in our question, we get
log2^3/2(x) = 1/(3/2)log2(x)
=> 2/3 log2 (x) = 10/3
=> log2(x) = (10/3)*(3/2)
=> log2(x) = 5
=> x = 2^5
=> x = 32.
Hence, the answer. :)
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