log b base a^2 ÷ log b^2 base sqrt. a
plzzz solve this
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log{b base a² }/log {b² base √a}
we know,
log{xⁿ base y } = n × log{x base y }
log{x base yⁿ} = 1/n × log{x base y }
1/2 log{b base a }/2 × 2 log{b base a}
= 1/8
we know,
log{xⁿ base y } = n × log{x base y }
log{x base yⁿ} = 1/n × log{x base y }
1/2 log{b base a }/2 × 2 log{b base a}
= 1/8
siimransiingh:
plz elaborate the last step.... how u got 1/8
did u cancel out log b base a with log b base a??
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