Question

log/b-c=log b/c-a =log c/ a-b then ​

Answer 1

Answer:

given=

log a/b-c=log b/c-a =log c/ a-b then ​

Step-by-step explanation:

Taking antilog both sides we get,

a/b-c=b/c-a=c/a-b

a(c-a)=b(b-c)------1)

b(a-b)=c(c-a)------2)

Solve the equations further.