Log(b)/log(a)=3/2 and log(d)/log(c)=5/4 and a-c=9 then b-d=?
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b = a3/2 ; d= c5/4
let a1/2 = x and c1/4 =y
then b = x3 and d = y5
given a-c = 9 or x2 - y4 = 9 or (x-y2)(x+y2)=9
we have to find two factors of 9 which are integers
now ; 9 can be expressed as 9x1 or 3x3
i.e. if we breadth 9 as 3x3 then x-y2 = x+y2 which is not possible for any existing integer
therefore x-y2 = 1 and x+y2 = 9
adiing the two equations we get 2x = 10 or x=5
and if x = 5 then y = 1
therefore b = 125 and d =32
therefore b-d = 83
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