Math, asked by vendotijyosthana, 1 month ago

log base 0.5 x square < log base 0.5 25 then the value of x​

Answers

Answered by Anonymous
0

Answer:

x≤-5   OR    x≥5

Step-by-step explanation:

\log_{0.5} x^2 &lt; \log_{0.5} 25\\\ x^{2}&gt;25     [\ Because\ base \ is\  less\  than \ 1, so \ sign\  changes]\\\ x&gt; \sqrt25\\\\By wavy curve method\\\ x \leq -5  \ OR   \ x\geq 5

Answered by qwsuccess
0

The answer is x ∈ (-5, 5).

Given: log_{0.5} x^{2} &lt; log_{0.5} 25

To find: the value of x

Solution:

We know that,

log_{0.5} x^{2} &lt; log_{0.5} 25

⇒ x² < 25 [∵ same base]

⇒ -5 < x < 5

x ∈ (-5, 5) Answer

SPJ2

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