Log base 10(log base 10(log base 10x)=0,then value of x is?
Answers
Answered by
6
Given
we have given log₁₀(log₁₀(log₁₀ₓ)=0
To Find
we have to find value of x
Now ,we see that all log are in product form
So,we first open the brackets and simply multiply the log :
=>log₁₀×log₁₀×log₁₀ₓ=0
logarithmic properties:
Log m × log n= logm + log n
log₁₀×log₁₀ can also be written as log²₁₀ = 2log₁₀=log₁₀+log₁₀
=>log₁₀+log₁₀×log₁₀ₓ=0
=>log₁₀+(log₁₀+log₁₀ₓ)=0
=>log₁₀+log₁₀+log₁₀ₓ=0
=>2log₁₀= -log₁₀ₓ
For two functions to be be equal the arguments of that function must be equal.
So,the exact value for x will be
x= 1/1000
or x = 0.001
Other logarithmic properties:
- log m-logn = logm÷ logn
- log base e = 1
- log 1 = 0
Similar questions