Question

log base 2 [ -1+ √ x^2- 14x + 49 ] = 4​

Answer 1

y = √(3x+5)+7

Inverse:

x = √(3y+5)+7

x-7 = √(3y+5)

(x-7)^2 = √(3y+5)^2

(x-7)(x-7) = 3y+5

x^2-7x-7x+49 = 3y+5

x^2-14x+49 = 3y+5

x^2-14x+49-5 = 3y

x^2-14x+44 = 3y

(x^2-14x+44) = 3y

(x^2-14x+44)/3 = y

Answer: f(x)=(x^2-14x+44)/3