Question

Log base 2 32 +log base 81 x=11/2 then find the value of x

Answer 1

Answer:

log ₂ 32 + log ₈₁ x = 11 / 2

log ₂ 2⁵ + log ₈₁ x = 11 / 2

5 log ₂ 2 + log ₈₁ x = 11 / 2

We know log ₓ x = 1

5  + log ₈₁ x = 11 / 2

log ₈₁ x = 11 / 2 - 5

log ₈₁ x = 1 / 2

Now as writing in exponent form :

$\displaystyle{81^{1/2} = x }$

x = √ 81

x = 9.

Therefore , value of x is 9 .