Math, asked by krishnagupta9746, 9 months ago

Log base 2 of x +log base 8 of x^3 = 4 then find the value of x

Answers

Answered by Bill5678
0
Log x / log 2 + log x^3 / log 8 = 4
Log (x -2) + log ( x^3-8) = 4
( x-2) ( x^3-8) = 4

X-2 = 4
X = 6

X^3 -8 = 4
X^3 = 12
X = +- 2 sqrt 3

Although there are 3 solutions, the negative root won’t be taken into account as it does not exist in the domain
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