log base 2^(x+2)=log16, so what will be the value of x
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Answer:
log₂ (x+2) = log 16
2log(x+2) / log = 16
2 (x+2) = 16
2x + 4 = 16
2x = 16 - 4
2x = 12
x = 12/2
x = 6
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