Question

log base 3 27+log base 3 12-log base 3 4=x​

Answer 1

Answer:

what is the ?

Step-by-step explanation:

i dont get this line you wrote

Answer 2

SOLUTION

GIVEN

$\displaystyle \sf{ log_{3}(27) + log_{3} ( 12) - log_{3}(4) = x }$

TO DETERMINE

The value of x

FORMULA TO BE IMPLEMENTED

We are aware of the formula on logarithm that

$\sf{1. \: \: \: log( {a}^{n} ) = n log(a) }$

$\sf{2. \: \: log(ab) = log(a) + log(b) }$

$\displaystyle \sf{3. \: \: log \bigg( \frac{a}{b} \bigg) = log(a) - log(b) }$

$\sf{4. \: \: log_{a}(a) = 1}$

EVALUATION

$\displaystyle \sf{ log_{3}(27) + log_{3} \bigg( 12\bigg) - log_{3}(4) = x }$

$\displaystyle \sf{ \implies log_{3}( {3}^{3} ) + log_{3} \bigg( \frac{12}{4} \bigg) = x }$

$\displaystyle \sf{ \implies 3 log_{3}( {3}^{} ) + log_{3} (3) = x }$

$\displaystyle \sf{ \implies (3 \times 1) + 1 = x }$

$\displaystyle \sf{ \implies x = 3 + 1}$

$\displaystyle \sf{ \implies x = 4}$

FINAL ANSWER

Hence the required value of x = 4

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