Question

log base 3 (x^2-5x+7) <0

Answer 1

Step-by-step explanation:

x^2-5x+7<3^0

x^2-5x+7<1

x^2-5x+7-1<0

x^2-5x+6<0

x^2-3x-2x+6<0

x(x-3)-2(x-3)<0

(x-3)(x-2)<0

now draw the number line and divide into 3 parts

such as after 3 and between 2 and 3 and less than 2

now take some value after 3 put that in the above inequality

so you get positive

but we need less than 0 so we don't want so

next will - and positive by wave curvy method

so x values should be inbetween 2 and 3

(2,3)