log(base)4 x +logb(base)3 x = 9 then the value of x is?
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Step-by-step explanation:
log a base b = log a/ log b
logx logx
___ + ____ = 9
log4 log3
log x * (1/log4 + 1/ log3) = 9
log x= 9 ÷(log 4 + log3 / log4*log3)
=9 ÷(log(4×3)/ log4*log3)
= 9÷(log 12/(log4 * log3))
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