Question

log base (e) e^2 answer

Answer 1

=log e<e>^2
=2log e<e> [rule:log e<e>^m=mlog e<e>]
=2(1) [rule:log e<e>=1]
=2

Answer 2

$log_{e}( {e}^{2} ) \\ \\ = 2log_{e}( {e} ) \\ using ...\: log_{e}( {x}^{n} ) = n log_{e}(x) \\ \\ = > log_{e}( {e}^{2} ) \: = 2 \times 1 = 2$