Question

log base x-3 (log base 2x square-2x+3(x2+2x))=0

Answer 1

Answer:

x=1 or x=3

Step-by-step explanation:

$\log_{x-3} (\log_{2x^{2}-2x+3} (x^{2}+2x))=0\\\log_{2x^{2}-2x+3} (x^{2}+2x)=1\\\ x^{2}+2x=2x^{2}-2x+3\\\ x^{2}-4x+3=0\\\ x^{2}-3x-x+3=0\\\ x(x-3)-1(x-3)=0\\\ (x-1))(x-3)=0\\\ x=1\\or\\ x=3$