log(base10)16 +log (base10)9=
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Answered by
1
=log₁₀16+log₁₀9
=log16/log10+log9/log10
=2log4+2log3
=2(log4+log3)
=2(log12)
=log144
=log16/log10+log9/log10
=2log4+2log3
=2(log4+log3)
=2(log12)
=log144
Answered by
2
Hello!
Note :- As all the bases are of 10, I amn't mentioning them
log16+log9
log 2⁴+log 3²
4log2+2log3
log2=0.3( rounded)
log 3=0.4 (rounded)
4*0.3+2*0.4
1.2+0.8
=2
The answer is 2 approximately
(or)
log16+log9
log(16*9)
log144
=2.1584
★ hope helped ★
Note :- As all the bases are of 10, I amn't mentioning them
log16+log9
log 2⁴+log 3²
4log2+2log3
log2=0.3( rounded)
log 3=0.4 (rounded)
4*0.3+2*0.4
1.2+0.8
=2
The answer is 2 approximately
(or)
log16+log9
log(16*9)
log144
=2.1584
★ hope helped ★
mysticd:
Second one is correct
Log144 is enough
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