Question

log(base4)(2) + log(base9)(2x+5) = log(base 8)(64)

Answer 1

Explanation:

$log_{4}2+log_{9}(2x+5)=log_{8}64$

$\frac{1}{2} + log_{9}(2x+5)= 2$

$log_{9}(2x+5)=\frac{3}{2}$

$9^\frac{3}{2} = 2x + 5$

$2x + 5 = 3^3$

$2x + 5 = 27$

$2x = 22$

∴ $x = \frac{22}{2}=11$

Answer: x = 11

I hope this answer helps. :D