Question

log(c+b) a +log(c-b) a
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log(c+b) a. log(c-b) a​

Answer 1

Answer:

log(c+b)a+log(c-b)a

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log(c+b)a.log(c-b)a

All has same base so,

=log(c+b)a×(c-b)a

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log (c+b)a.(c-b)a

= log (c^2-b^2)a^2

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log(c^2-b^2)a^2

if we have log a base b we can write it as log a base a/ log b base a from this we have:

= log (c^2-b^2)a^2 base( c^2-b^2)a^2

=1