Log cos ^(-1) (x) differentiate this function
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Answer:
When tackling the derivative of inverse trig functions. I prefer to rearrange and use Implicit differentiation as I always get the inverse derivatives muddled up, and this way I do not need to remember the inverse derivatives. If you can remember the inverse derivatives then you can use the chain rule.
Let
y
=
cos
−
1
(
x
)
⇔
cos
y
=
x
Differentiate Implicitly:
−
sin
y
d
y
d
x
=
1
..... [1]
Using the
sin
/
cos
identity;
sin
2
y
+
cos
2
y
≡
1
∴
sin
2
y
+
x
2
=
1
∴
sin
2
y
=
1
−
x
2
∴
sin
y
=
√
1
−
x
2
Substituting into [1]
∴
−
√
1
−
x
2
d
y
d
x
=
1
∴
d
y
d
x
=
−
1
√
1
−
x
2
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