Math, asked by shekhar1158, 1 year ago

log(cos e^x) differ​

Answers

Answered by Lekahdek
0

Hey mate!

Here's your answer!

d \div dx( log( \cos(e^{x} ))  \\  =  > 1 \div  \cos(e {}^{x} )  \times  -  \sin(e^{x} )  \times e {}^{x} \\  =  >  - e {}^{x}  \tan(x).

Hope it helps :)


ammuisthebest3890: hi rashi kanna
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