Math, asked by akshith31641, 7 months ago

log log log
x x x
x x x
abc
bca
       
  

Answers

Answered by swe15
0

Answer:

x = log abc 1 + x = logb+ logcloga + 1 1 + x = logb+logc+logaloga [ logab = logbloga & log(ab) = log a + log b] ...(1) similarly 

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